Feature #15973
closedLet Kernel#lambda always return a lambda
Added by alanwu (Alan Wu) about 5 years ago. Updated almost 3 years ago.
Description
When Kernel#lambda receives a Proc that is not a lambda,
it returns it without modification. l propose to change Kernel#lambda
so it always returns a lambda.
Calling a method called lambda and having it do nothing in effect is
not very intuitive.
https://github.com/ruby/ruby/pull/2262
Judging from marcandre's investigation here: https://bugs.ruby-lang.org/issues/15620#note-1,
changing the behavior should not cause much breakage, if any.
This also happens to fix [Bug #15620]
Updated by matz (Yukihiro Matsumoto) about 5 years ago
I agree. Even though we have to investigate how big the consequence of the change first.
Matz.
Updated by alanwu (Alan Wu) about 5 years ago
- Subject changed from Make Kernel#lambda always return lambda to Make it so Kernel#lambda always return a lambda
Updated by Eregon (Benoit Daloze) about 5 years ago
I'm not sure changing this is good, because it can be very surprising for the code to change semantics dynamically.
Also, should proc(&lambda)
make a non-lambda Proc then? It would be inconsistent if not.
As I said in https://bugs.ruby-lang.org/issues/15620#note-2, the current rule is AFAIK only change the semantics if a block is directly given, because the programmer means to use those semantics then.
If not, don't change the semantics as it would break the user (the Proc's code)'s intention.
The only exception to this is define_method
with a pre-existing Proc
, which is very rare, and understandably needed because methods should check arguments strictly. (maybe we don't need that exception)
I believe #15620 should be fixed on its own, it's a bug of the optimization.
Here is an example (a bit contrived, I'm tired):
def foo(arg)
early_check = Proc.new {
# everything here assumes it will always be proc/non-lambda semantics
return :early_return if arg > 3
}
# Some way for some external code to access `early_check`
early_check = yield early_check
early_check.call
:method_return_value
end
p foo(4) { |pr| lambda(&pr) }
With current semantics, it returns :early_return
.
With the proposed change, it returns :method_return_value
.
That's very surprising, isn't it? The code clearly means it wants a non-local return to exit the method,
and yet somehow it was transformed into a local lambda return!
I think such a surprising transformation of user code should happen as little as possible, so I'm against this proposal.
Maybe we should simply forbid calling proc
/lambda
without a literal block (i.e., with an explicit Proc like lambda(&pr)
), since it doesn't do anything useful ?
That would make more sense to me, and be in line with @ko1's recent changes to disallow things like Proc.new
, etc without a block.
Updated by shyouhei (Shyouhei Urabe) about 5 years ago
- Related to Feature #12957: A more OO way to create lambda Procs added
Updated by shyouhei (Shyouhei Urabe) about 5 years ago
- Related to Feature #7314: Convert Proc to Lambda doesn't work in MRI added
Updated by shyouhei (Shyouhei Urabe) about 5 years ago
No. I'm against it. We have discussed this before multiple times. See the issues I linked just now.
Updated by alanwu (Alan Wu) about 5 years ago
The 2.4 spec is a bit problematic since it makes it impossible to forward a
block to Kernel#lambda
with a block pass. In the rest of the language
forwarding a block has no effect on semantics compared to passing one
literally. The idea of literal blocks being different from non-literal ones
exists only in the case of Kernel#lambda
.
A concept at odds with the rest of the language specific to one single method
is sure to surprise. Special one-off concepts make the language harder to learn
and add complications to implementaitons.
As others have pointed out, it's already possible to transform a proc into a
lambda-proc via define_method
. My proposal isn't adding anything new with
regards to messing with the perscribed usage of code within blocks.
Transforming a proc into a lambda-proc is certainly a sharp tool. For me it
falls in the same category as instance_variable_set
and const_set
. However,
I think the situation in which it ends up being surprinsg is very rare.
return
within a Proc.new do ...
comes up rarely as is.
Is "someone might misuse this in specific sutations" a good reason to keep an
ad-hoc concept in the language? For me, no.
Updated by alanwu (Alan Wu) about 5 years ago
I would also like to note that if we revert back to the behavior in 2.4, code that relied on lambda
without block will not have an easy upgrade path.
def make_a_lambda
lambda
end
is not equivalent to
def make_a_lambda(&block)
lambda(&block)
end
under 2.4 spec.
Updated by shyouhei (Shyouhei Urabe) about 5 years ago
"It's already broken, why not break it more" is not what I can follow.
Can I ask you why you need this feature? If this not more than a matter of consistency, I would like to second @eregon's proposal: lambdas without literal blocks to be prohibited at all.
Updated by alanwu (Alan Wu) about 5 years ago
Can I ask you why you need this feature?
I want to be able to forward a block to Kernel#lambda
.
Kernel#lambda
is in a weird spot. Even though it's a method, making it behave like one has the unfortunate side-effect of allowing proc transformation.
On the other hand, restricting it to just literal blocks is fairly magical and makes it just another way to do stabby lambda.
It seems like there is no perfect solution here.
I don't feel too strongly about my proposal. Banning block-pass to Kernel#lambda
sounds good to me too if others are not comfortable with making proc-to-lambda transformation more accessible.
Updated by Eregon (Benoit Daloze) about 5 years ago
alanwu (Alan Wu) wrote:
Kernel#lambda
is in a weird spot. Even though it's a method, making it behave like one has the unfortunate side-effect of allowing proc transformation.
Yes, the semantics of Kernel#lambda
have always been a bit weird because no method should be allowed to convert a Proc to a lambda and inversely.
And visually, lambda { ... }
receives a block, which is a non-lambda Proc.
My point of view is lambda
is a relic of the past, and we should use -> { ... }
instead, which has clear semantics and obviously you can't pass a pre-existing block to it.
Yes, I think we should raise lambda(&existing_block)
as that can't behave intuitively (it seems either useless or confusing).
Updated by akr (Akira Tanaka) about 5 years ago
I'm against it.
Changing lambda <-> proc can violate the intent of programmers who write a block.
It seems good to raise an exception at lambda(&b)
where b is (non-lambda) proc.
Updated by matz (Yukihiro Matsumoto) about 5 years ago
In my opinion, lambda
should return lambda
object as a principle. We need to keep the discussion.
Maybe we can generate a delegating lambda object in this case.
Matz.
Updated by knu (Akinori MUSHA) about 5 years ago
I don't think the lambda flag should be altered after the creation of a proc, because it's all up to the writer of a block how return
/break
etc. in it should work.
What about just deprecate lambda
in the long run in favor of the lambda literal ->() {}
?
Updated by marcandre (Marc-Andre Lafortune) about 5 years ago
knu (Akinori MUSHA) wrote:
I don't think the lambda flag should be altered after the creation of a proc, because it's all up to the writer of a block how
return
/break
etc. in it should work.
akr wrote similar opinion.
This same opinion would call for deprecation of define_method(&block)
, which I believe would be a mistake.
I am assuming it is clear that lambda(&block)
would never mutate block
and return a new object that would be a lambda.
Updated by shyouhei (Shyouhei Urabe) about 5 years ago
Suppose we change the spec so that lambda(&nonlambda)
generates a lambda.
Suppose we have the following nonlambda proc:
1: foldr = proc do |x, *xs|
2: foo(x, foldr.(xs)) if x ||! xs.empty?
3: end
A straight-forward foldr implementation, with foo
defined elsewhere.
Now let's "convert" it into a lambda:
4: foldr = lambda(&foldr)
This magically breaks the program. The meaning of |x, *xs|
changed.
The problem I see is that the broken program would generate a backtrace like this:
Traceback (most recent call last):
5444: from tmp.rb:2:in `block in <main>'
5443: from tmp.rb:2:in `block in <main>'
5442: from tmp.rb:2:in `block in <main>'
5441: from tmp.rb:2:in `block in <main>'
5440: from tmp.rb:2:in `block in <main>'
5439: from tmp.rb:2:in `block in <main>'
5438: from tmp.rb:2:in `block in <main>'
... 5433 levels...
4: from tmp.rb:2:in `block in <main>'
3: from tmp.rb:2:in `block in <main>'
2: from tmp.rb:2:in `block in <main>'
1: from tmp.rb:2:in `block in <main>'
tmp.rb:2:in `block in <main>': stack level too deep (SystemStackError)
There is no single bit of information that the prolem is caused by that lambda conversion.
An end user has no other way than to blame tmp.rb:2 not tmp.rb:4, because the backtrace says so.
This is really bad. Think of for instance the block was from another library. The library authors suddenly get angry bug reports due to some random other guy turned their proc into lambda. This is nonsense.
Non-lambda to lambda conversion disturbs the boundary point of responsibility. Should not be allowed I believe.
Updated by alanwu (Alan Wu) about 5 years ago
The idea to generate a delegating lambda seems to side-step a lot of the issues posted here.
For reference here are some quotes from the log in #15930 (courtesy of ko1):
b = proc {|x| x }
lambda(&b) #=> lambda {|x| b[x] }
b = proc {|x, y, k:1| x }
lambda(&b) #=> lambda {|x, y, k:1| b[x, y, k:k] }
This preserves the return
semantics in the original proc. I would imagine it would also add an entry to the call stack.
(side note, I think the default parameter evaluation has to be left to the original proc too since a return
could be in there)
What do you folks think about this?
Updated by akr (Akira Tanaka) about 5 years ago
- Related to Feature #9777: Feature Proposal: Proc#to_lambda added
Updated by akr (Akira Tanaka) about 5 years ago
- Related to Feature #8693: lambda invoked by yield acts as a proc with respect to return added
Updated by shyouhei (Shyouhei Urabe) about 5 years ago
Yes, I can compromise with delegation scheme, as long as it leaves its own frame in the call stack. An optional method for a proc to prevent such delegation is desirable but can be added later.
Updated by akr (Akira Tanaka) about 5 years ago
Eregon (Benoit Daloze) wrote:
With current semantics, it returns
:early_return
.
With the proposed change, it returns:method_return_value
.
That's very surprising, isn't it?
I agree.
The lambda-ness of Proc object affects control flow: the behavior of "return" and "break".
If lambda(&b) changes the lambda-ness of b, two control flow can exist.
I think no programmer want to consider two control flow when implementing one block.
Updated by Eregon (Benoit Daloze) about 5 years ago
alanwu (Alan Wu) wrote:
The idea to generate a delegating lambda seems to side-step a lot of the issues posted here.
So then, would it be the same semantics as this?
b = proc {|x, y, k:1| x }
l = lambda { |*args, **kwargs, &block| b.call(*args, **kwargs, &block) }
I think the lambda cannot have the same (in the code) arguments as the proc, otherwise https://bugs.ruby-lang.org/issues/15973#note-16 would fail too.
@alanwu (Alan Wu) Can you present use case(s) for turning procs into lambdas?
So far I only see consistency but the delegating lambda is not that consistent with #lambda with a literal block.
Without a good use-case, I think raising on #lambda without a literal block would be the safest and least surprising.
Updated by Eregon (Benoit Daloze) about 5 years ago
- Related to Bug #16004: Kernel#lambda captured with Kernel#method doesn't create lambdas added
Updated by alanwu (Alan Wu) about 5 years ago
Can you present use case(s) for turning procs into lambdas?
One use case is reading the parameters of blocks as if they were written for a method definition: https://bugs.ruby-lang.org/issues/9777#note-11
Another one is getting lambda style parameter checking for the incoming block. msgpack-ruby does this through the CAPI: https://github.com/msgpack/msgpack-ruby/blob/b48f9580bfd33be6a86652f10a41bd691a7d0c91/ext/msgpack/unpacker_class.c#L367
I asked for opinions about the delegation scheme because it seems like a good way to go if we must return a lambda. At the time I didn't make up my mind as to whether it would be a good idea to return one.
I now believe that banning everything but the literal block form lambda is overall better. lambda
being a method exposes it to many different ways of calling it, some of which don't have obvious semantics.
We can pick a semantic for lambda(&thing), but there will always be some percentage of users that find the behavior surprising. We can minimizes surprises, but we can't eliminate it, as long
as lambda
is a method.
To illustrate, here are two more ways to call into Kernel#lambda
that are hard to define good semantics for: super
(zsuper) and method(:lambda).call {}
. Right now zsuper creates a lambda while
method(:lambda).call {}
doesn't. I'm not sure what these should do and different people probably have different ideas.
I think lambda
was supposed to be a psudo-keyword but implementing it as a method is unfortunately exposing it to a whole array of usages that were not considered.
If we can promote it to a psudo-keyword, that would be best. Failing that, banning lambda(&thing)
at least removes one source of surprise with clear messaging.
Updated by Dan0042 (Daniel DeLorme) about 5 years ago
I think the delegating lambda idea doesn't really work. I mean, it doesn't do anything. You just get a lambda that behaves like a proc. It just changes the return value of Proc#lambda?
which I don't think has any benefit by itself. In fact it might be counterproductive to hide the fact that this Proc object really behaves like a proc and not a lambda.
It seems the main use case for proc->lambda conversion is to validate the Proc defines the correct parameters? But I believe it's quite ok to let the writer of the Proc worry about that. And if you really want a lambda you should just enforce it.
def foo(lambda)
lambda.lambda? or raise ArgumentError
lambda.call(1,2,3)
end
foo -> (x) do
42
end
#=> ArgumentError (wrong number of arguments (given 3, expected 1))
So I haven't yet seen a single good use case for this conversion, and I can't think of one despite trying. You'd need a situation where you want a Proc to have either proc or lambda behavior based on a condition. That's....
On the other hand there's a good case to make for just letting the programmer do what s/he wants. If you want to convert a proc into a lambda presumably you have a reason for doing so, and understand the consequences. The only real danger is if a proc was converted to a lambda inadvertently . But I can't come up with a realistic situation where this could occur. All the "surprising" examples I've seen are contrived and in fact not surprising at all. If a method expects a proc and you give it a lambda, that's no different than giving it an Integer or any other object that fails expectations. I honestly can't think of a situation where you'd want lambda(&myproc)
to just pass through the proc unchanged; if you don't want to convert you'd just use myproc
directly, right?
In the end it seems the only benefit of proc<->lambda conversion is for the sake of consistency of the proc
and lambda
methods? I guess that makes some sense, because this situation is definitely weird and surprising:
lambda{ } #=> #<Proc:0x000055e295d1d648@(irb):1 (lambda)>
class X;def lambda;super;end;end; X.new.lambda{ } #=> #<Proc:0x000055e295d0b0d8@(irb):2 (lambda)>
lambda(&proc{ }) #=> #<Proc:0x000055e295d08d88@(irb):3>
method(:lambda).call{ } #=> #<Proc:0x000055e295d01da8@(irb):4>
def foo(&b);lambda(&b);end; foo{ } #=> #<Proc:0x000055e295cf4810@(irb):6 (lambda)>
Updated by ko1 (Koichi Sasada) about 5 years ago
- Status changed from Open to Assigned
- Assignee set to matz (Yukihiro Matsumoto)
does anyone can write a discussion summary? :p
Updated by matz (Yukihiro Matsumoto) about 5 years ago
I agree with @akr (Akira Tanaka) here, as long as lambda
with a block argument warns.
We need to keep compatibility. But I think we should warn this inconsistent behavior.
Matz.
Updated by Dan0042 (Daniel DeLorme) about 5 years ago
akr (Akira Tanaka) wrote:
The lambda-ness of Proc object affects control flow: the behavior of "return" and "break".
If lambda(&b) changes the lambda-ness of b, two control flow can exist.
I think no programmer want to consider two control flow when implementing one block.
I think everyone can agree with that. The issue I guess is should it be allowed to define a lambda using block syntax, with the two main viewpoints being
A. lambda()
and define_method()
already allow this, so it's a well established pattern. So why not allow my_anonymous_function_dsl{ }
? In this case the one writing the block knows it's supposed to have lambda semantics. In 2.5 it became allowed in certain circumstances but that was apparently unintended (#15620)? A search through major gems showed no incompatibilities. Numerous tickets through the years indicate current behavior is surprising to many.
B. lambda()
and define_method()
should never have allowed this; proc/lambda semantics should be defined lexically. Changing it dynamically is surprising. We can't break compatibility but we should not dig ourselves any deeper. Use my_anonymous_function_dsl&->{ }
instead. It's a change in behavior so there may be incompatibility issues.
Does this seem like an accurate summary?
Updated by Dan0042 (Daniel DeLorme) about 5 years ago
This may be irrelevant but I would like to point out that proc->lambda conversion was supported in ruby 1.8
b = Proc.new{ return 42 }
b.call #=> LocalJumpError: unexpected return
lambda(&b).call #=> 42
I'm not sure if the change was intentional or not, but this feature request is really about restoring lost behavior, not introducing new one. :-)
Updated by sawa (Tsuyoshi Sawada) about 5 years ago
- Subject changed from Make it so Kernel#lambda always return a lambda to Let Kernel#lambda always return a lambda
- Description updated (diff)
Updated by alanwu (Alan Wu) almost 5 years ago
I have updated my fix for [Bug #15620] to also issue a warning in cases it
returns the argument it receives without modification.
Since both 2.5.x and 2.6.x has [Bug #15620], there may be code in the wild that
depend on the unintended lambda conversion behavior. It might make sense to
put the 2.4.x behavior back for 2.7.0-preview2 to find out whether it's an
issue.
Updated by Eregon (Benoit Daloze) over 4 years ago
- Related to Bug #15620: Block argument usage affects lambda semantic added
Updated by Eregon (Benoit Daloze) over 4 years ago
- Target version set to 36
@matz (Yukihiro Matsumoto) Is it OK to warn for this in the next Ruby version?
I think it's going to highlight wrong usages (good) and I would expect there are very few usages of lambda(&existing_proc)
.
The warnings were implemented in https://github.com/ruby/ruby/pull/2289 by @alanwu (Alan Wu) but @ko1 (Koichi Sasada) said we should postpone them as it's too late for 2.7:
https://github.com/ruby/ruby/pull/2289#issuecomment-567820054
Updated by ko1 (Koichi Sasada) over 4 years ago
This is one idea: how about to prohibit lambda(&...)
method call? (block literal is always prohibited)
3.0: deprecation warning and show 3.1 will raise exception for lambda(&...)
3.1: raise exception for lambda(&...)
same as proc
.
Updated by ko1 (Koichi Sasada) over 4 years ago
more aggressive proposal is obsolete lambda
call, and use ->
(maybe it is too aggressive).
Updated by Eregon (Benoit Daloze) over 4 years ago
ko1 (Koichi Sasada) wrote:
This is one idea: how about to prohibit
lambda(&...)
method call? (block literal is always prohibited)
I think you mean non-literal block (&
) becomes prohibited.
3.0: deprecation warning and show 3.1 will raise exception for
lambda(&...)
3.1: raise exception forlambda(&...)
same as
proc
.
And whether it's lambda(&...)
or lambda { }
is detected by the lambda method itself (like for the warning)?
That sounds good to me.
Updated by Eregon (Benoit Daloze) over 4 years ago
ko1 (Koichi Sasada) wrote:
more aggressive proposal is obsolete
lambda
call, and use->
(maybe it is too aggressive).
Sounds even better to me, but I guess that might be disruptive for everyone to adopt -> {}
style.
It would be interesting to see what matz thinks about this.
->
exists since at least 2.0, so it shouldn't be a compatibility issue to use it.
From the point of view of a Ruby VM, not having to handle #lambda
magically changing the semantics of the passed block would be great,
because it's really awkward and hard to check if the block is literal or not (considering lambda
can be alias
-ed).
It would also simplify the semantics for the user: method_call { ... }
is always a non-lambda Proc, and -> {}
is the only way for a lambda.
Updated by Eregon (Benoit Daloze) over 4 years ago
On a related note I think we should also prohibit define_method(&non_lambda)
because that confusingly treats the same block body differently (e.g., the same return
in the code means something different).
Updated by zverok (Victor Shepelev) over 4 years ago
On a related note I think we should also prohibit
define_method(&non_lambda)
because that confusingly treats the same block body differently (e.g., the same return in the code means something different).
Seem it will have an awful impact on any DSLs?..
Like
skip_if { |user| user.admin? }
# ...implemented as
def skip_if(&condition)
define_method(:skip?, &condition)
end
Updated by Eregon (Benoit Daloze) over 4 years ago
zverok (Victor Shepelev) wrote:
Seem it will have an awful impact on any DSLs?..
Which is IMHO a perfect example of how dangerous that is.
What if it's skip_if { |user| return 42 }
?
Do you expect that to return from the surrounding method or to return from the block?
For any non-lambda Proc it should mean return from the surrounding method, define_method
breaks that (by converting a proc to a lambda implictly).
# Assuming your definition of skip_if
skip_if { |user| return 42 } # should return from the surrounding method but does not
skip?(1) # but it does not, it just returns from the block!
proc { |user| return 43 }.call # returns from the surrounding method
raise "unreachable" # never reached, as expected
There is an easy workaround:
def skip_if(&condition)
define_method(:skip?, -> *args { condition.call(*args) })
end
With that skip?(1)
returns from the surrounding method, as it should like every other literal block.
Updated by zverok (Victor Shepelev) over 4 years ago
Ugh, let me be a bit philosophical here (how many times I promised myself to not engage in discussions about Ruby's "spirit"? I've lost count.)
I understand the point you are speaking from (language implementer's background, who constantly fights with "dangerously illogical" parts), but for me, one of the key points of Ruby's attractiveness is how far it goes to reduce boilerplate in a logical and humane way. There is a non-neglectible gap between "human" consistency and "computer" (formal) consistency.
I am writing in Ruby for >15 years now (and teaching it for >5 years, and blah-blah-blah). I've implemented and used metric shit-ton of DSLs. So, for me and my intuition is experience, it is just this way:
skip_if { |user| return 42 }
...is something that will behave "unexpectedly"? Yes.
Have I met a lot of cases when it was really written and shot somebody in the head? No.
What if somebody really happens to meet with this case and is surprised? I believe they'll spend some time to wrap they head about it. That's a price we pay to have "complex language for writing simple code".
Now, when I see this:
def skip_if(&condition)
define_method(:skip?, &condition)
end
...which "should" be "simply workarounded" to this:
def skip_if(&condition)
define_method(:skip?, -> *args { condition.call(*args) })
end
...I see it as "your language implementation is really busy doing its important things. So it will not help you to write clean and obvious code. I (language implementation) see what you want to do (define methods implementation from a block in the variable), and I know how to fix it (block should be converted to lambda), but you (puny human) should do it with your own soft hands".
It can and will harm the will to write simple helping DSLs (which, one may argue, "is a good thing" anyways?..)
Why, then, bother with "all this proc vs lambda nonsense" (as some may, and do, argue)? All in all, "you don't need this complexity at all", right? Because
sources.zip(targets).map { |src, tgt| tgt.write(src) }
...can be "easily workarounded" as this:
sources.zip(targets).map(->(arguments) { arguments[1].write(arguments[0]) } }
...and everything suddenly becames more consistent and homogenous...
We can go this way really far, honestly :)
Updated by ko1 (Koichi Sasada) over 4 years ago
Ok, make a new ticket about define_method. How about lambda?
Koichi
2019/12/26 4:34、zverok.offline@gmail.comのメール:
Issue #15973 has been updated by zverok (Victor Shepelev).
Ugh, let me be a bit philosophical here (how many times I promised myself to not engage in discussions about Ruby's "spirit"? I've lost count.)
I understand the point you are speaking from (language implementer's background, who constantly fights with "dangerously illogical" parts), but for me, one of the key points of Ruby's attractiveness is how far it goes to reduce boilerplate in a logical and humane way. There is a non-neglectible gap between "human" consistency and "computer" (formal) consistency.
I am writing in Ruby for >15 years now (and teaching it for >5 years, and blah-blah-blah). I've implemented and used metric shit-ton of DSLs. So, for me and my intuition is experience, it is just this way:
skip_if { |user| return 42 }
...is something that will behave "unexpectedly"? Yes.
Have I met a lot of cases when it was really written and shot somebody in the head? No.
What if somebody really happens to meet with this case and is surprised? I believe they'll spend some time to wrap they head about it. That's a price we pay to have "complex language for writing simple code".Now, when I see this:
def skip_if(&condition) define_method(:skip?, &condition) end
...which "should" be "simply workarounded" to this:
def skip_if(&condition) define_method(:skip?, -> *args { condition.call(*args) }) end
...I see it as "your language implementation is really busy doing its important things. So it will not help you to write clean and obvious code. I (language implementation) see what you want to do (define methods implementation from a block in the variable), and I know how to fix it (block should be converted to lambda), but you (puny human) should do it with your own soft hands".
It can and will harm the will to write simple helping DSLs (which, one may argue, "is a good thing" anyways?..)
Why, then, bother with "all this proc vs lambda nonsense" (as some may, and do, argue)? All in all, "you don't need this complexity at all", right? Because
sources.zip(targets).map { |src, tgt| tgt.write(src) }
...can be "easily workarounded" as this:
sources.zip(targets).map(->(arguments) { arguments[1].write(arguments[0]) } }
...and everything suddenly becames more consistent and homogenous...
We can go this way really far, honestly :)
Feature #15973: Let Kernel#lambda always return a lambda
https://bugs.ruby-lang.org/issues/15973#change-83402
- Author: alanwu (Alan Wu)
- Status: Assigned
- Priority: Normal
- Assignee: matz (Yukihiro Matsumoto)
- Target version: 2.8
When Kernel#lambda receives a Proc that is not a lambda,
it returns it without modification. l propose to changeKernel#lambda
so it always returns a lambda.Calling a method called lambda and having it do nothing in effect is
not very intuitive.https://github.com/ruby/ruby/pull/2262
Judging from marcandre's investigation here: https://bugs.ruby-lang.org/issues/15620#note-1,
changing the behavior should not cause much breakage, if any.This also happens to fix [Bug #15620]
Updated by Dan0042 (Daniel DeLorme) over 4 years ago
one of the key points of Ruby's attractiveness is how far it goes to reduce boilerplate in a logical and humane way. There is a non-neglectible gap between "human" consistency and "computer" (formal) consistency.
+1, very much. I'm glad there's still someone who cares about usefulness over "consistency"
Converting a proc to a lambda is very useful for DSLs. And generally speaking it's empowering to programmers. Maybe a bit dangerous, but I can take care of myself. I really don't need or want to be "protected" from powerful yet "unexpected" behaviors. This ticket was about making lambda
always return a lambda; at which point did it become about preventing this from happening?
I understand there's many who are emotionally invested into making ruby stricter and easier to implement/optimize, but at least there should be good alternatives for what the proc->lambda conversion allows.
For DSLs:
#a block is specified, and this DSL is documented to have lambda semantics, so we need to convert the proc to lambda
register_lambda(:xyz) do |x,y,z|
return x+y+z
end
#or a pretty syntax to pass a lambda as a block
register_lambda(:xyz)->(x,y,z) do
return x+y+z
end
#because this is ugly, honestly
register_lambda(:xyz, &->(x,y,z) do
return x+y+z
end)
Or what about:
block = proc{ |x,y,z=1| }
block.parameters #=> [[:opt, :x], [:opt, :y], [:opt, :z]]
# yes I know that all params are optional in a proc,
# but I wanted to know which have a default value and which don't
lambda(&block).parameters #=> [[:req, :x], [:req, :y], [:opt, :z]]
# this tells me what I wanted to know in a simple and easy way
Beyond the argument that this is dangerous (yes it is), there's also the fact that, used wisely, this is sometimes useful.
it's really awkward and hard to check if the block is literal or not (considering lambda can be alias-ed).
Then wouldn't it be really simple if all blocks were converted to lambdas regardless of being literal or not? KISS.
Updated by Eregon (Benoit Daloze) over 4 years ago
Yes, sorry I should not have mentioned define_method
here, even though it's related it's not the main topic.
I'll make a new issue for it (#16499).
Updated by Eregon (Benoit Daloze) over 4 years ago
- Related to Feature #16499: define_method(non_lambda) should not change the semantics of the given Proc added
Updated by ko1 (Koichi Sasada) over 4 years ago
Quote from today's devmeeting.
Discussion:
- Proposing to deprecate
lambda(&block)
(lambda
call withProc
object as block) - Benefits of obsoleting
lambda
?- Simplify for new Ruby developers. (no duplicated syntax.)
- Suspend for short term (for years)
- Don't want more incompatibilities just after Ruby 2.7
- Migration pass to deprecate
lambda(&block)
.- Print warning at 3.0. (No compatibility layer.)
- “The lambda call is meaningless. Delete it.”
- “Delete meaningless lambda”
- Raises error at 3.1 (or 3.2, ...)
- Print warning at 3.0. (No compatibility layer.)
Conclusion:
-
lambda(&b)
will be prohibited.- Print warning at 3.0. (No compatibility layer.)
- Raises error at 3.1 (or 3.2, ...)
Updated by jeremyevans (Jeremy Evans) about 4 years ago
- Status changed from Assigned to Closed
Applied in changeset git|2188d6d160d3ba82432c87277310a4d417e136d5.
Warn when passing a non-literal block to Kernel#lambda
Implements [Feature #15973]
Updated by hsbt (Hiroshi SHIBATA) almost 4 years ago
- Target version changed from 36 to 3.0
Updated by znz (Kazuhiro NISHIYAMA) over 3 years ago
- Related to Feature #17361: lambda(&block) does not warn with lazy proc allocation added
Updated by Eregon (Benoit Daloze) almost 3 years ago
@jeremyevans added a test for this in https://github.com/ruby/ruby/commit/2188d6d160d3ba82432c87277310a4d417e136d5#diff-8b146f8f5073c5ee6526a128c3e9c05ae7a52d2cd496f601351470137f2a87a0
but it was removed by @nobu (Nobuyoshi Nakada) in https://github.com/ruby/ruby/commit/996af2ce086249e904b2ce95ab2fcd1de7d757be#diff-8b146f8f5073c5ee6526a128c3e9c05ae7a52d2cd496f601351470137f2a87a0
And also this no longer warns, which sounds like a bug due to removing that test:
$ ruby -v -w -e 'p Warning[:deprecated]; p lambda(&:symbol)'
ruby 3.0.2p107 (2021-07-07 revision 0db68f0233) [x86_64-linux]
true
#<Proc:0x0000000001b07a38(&:symbol) (lambda)>
I guess maybe expected since Symbol#to_proc#lambda? is true (was false in 2.7)
And in that logic ruby -v -w -e 'p Warning[:deprecated]; p lambda(&lambda{})'
also doesn't warn.
This does warn as intended though, and we'll add a spec for it:
$ ruby -v -w -e 'p Warning[:deprecated]; p lambda(&proc{})'
ruby 3.0.2p107 (2021-07-07 revision 0db68f0233) [x86_64-linux]
true
-e:1: warning: lambda without a literal block is deprecated; use the proc without lambda instead
#<Proc:0x00000000020dfcf8 -e:1>