Feature #12957
closedA more OO way to create lambda Procs
Description
Currently to create a lambda Proc one has to use lambda { }
or -> { }
. For doing metaprogramming it would be nice to have a more OO way to generate them. Something like LambdaProc.new
. That way one could write:
class MetaThingy
def initialize proc_class
@anonymous_function = proc_class.new do
# Some Code
end
end
end
and pass in either Proc
or LambdaProc
depending on their needs, instead of:
class MetaThingy
def initialize proc_type
@anonymous_function = case proc_type
when :proc
proc do
# Some Code
end
when :lambda
lambda do
# Some Code
end
end
end
end
end
This is not a common use case, but would help make the language more orthogonal.
Updated by shyouhei (Shyouhei Urabe) almost 8 years ago
Problem is, when you allow LambdaProc.new, that have to accept non-lambda procs, like LambdaProc.new(&nonlambda). This way, a proc would be converted from/between lambda and non-lambda.
This is not a good idea. Right now a lambda is born to be a lambda and there is no way to turn it into a proc. If such property breaks, a programmer cannot guarantee what to expect to a block they wrote's parameter, because that proc can later be changed into a lambda by someone else. And there is no way to detect such change from that block itself before it is called.
Updated by shyouhei (Shyouhei Urabe) almost 8 years ago
- Related to Feature #7314: Convert Proc to Lambda doesn't work in MRI added
Updated by dsisnero (Dominic Sisneros) almost 8 years ago
I want this too
MyLambda = Class.new Proc
I want MyLambda{|x| x + 1}.lambda?
to == true
I only want it when initializing the new lambdas. I want easy initialization with a block
Maybe allow Proc.new
to accept true
or false
class Proc
def initialize(lmbda = false, &block)
if lmbda
__lambda__ = true
end
block = block
end
end
then
class MyLambda
def initialize(&block)
super(true,&block)
end
end
MyLambda.new{|x| x + 1}.lambda? == true
Updated by akr (Akira Tanaka) almost 8 years ago
- Status changed from Open to Feedback
It is not impossible to generate MyLambda.new {} as lambda.
% ruby -e '
class MyLambda
end
class << MyLambda
alias new lambda
public :new
end
x = MyLambda.new { p :foo }
p x.lambda?
x.call
'
true
:foo
I'm not sure this is enough for actual usages, though.
Updated by matz (Yukihiro Matsumoto) almost 8 years ago
The code above does not return a MyLamnda instance.
Matz.
Updated by Eregon (Benoit Daloze) almost 8 years ago
Actually, it is possible to create a single block of code that can be proc or lambda with #send:
> Kernel.send(:lambda) {}.lambda?
=> true
> Kernel.send(:proc) {}.lambda?
=> false
I was surprised as well this worked, the Kernel#lambda method is quite magic:
https://github.com/graalvm/truffleruby/pull/12#discussion_r96889356
Updated by shyouhei (Shyouhei Urabe) over 5 years ago
- Related to Feature #15973: Let Kernel#lambda always return a lambda added