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Bug #20324
closed`(1..).overlap?('foo'..)` returns true
Status:
Closed
Assignee:
-
Target version:
-
ruby -v:
ruby 3.3.0 (2023-12-25 revision 5124f9ac75) [arm64-darwin22]
Description
While thinking about finding the intersection of two ranges, I found that (1..).overlap?('foo'..)
returns true.
In the current implementation, it seems that (a..).overlap?(b..)
or (..a).overlap?(..b)
returns true regardless of what a
or b
are.
However, I think it should return true if and only if a
and b
are comparable.
(What is the intersection of 1..
and 'foo'..
?)
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