Bug #20324: `(1..).overlap?('foo'..)` returns true

• Status: Closed
• Assignee: -
• Target version: -
• ruby -v: ruby 3.3.0 (2023-12-25 revision 5124f9ac75) [arm64-darwin22]
• Backport: 3.0: DONTNEED, 3.1: DONTNEED, 3.2: DONTNEED, 3.3: REQUIRED

[kyanagi (Kouhei Yanagita)]

While thinking about finding the intersection of two ranges, I found that (1..).overlap?('foo'..) returns true.

In the current implementation, it seems that (a..).overlap?(b..) or (..a).overlap?(..b) returns true regardless of what a or b are.
However, I think it should return true if and only if a and b are comparable.
(What is the intersection of 1.. and 'foo'..?)

[nobu (Nobuyoshi Nakada)]

• Backport changed from 3.0: UNKNOWN, 3.1: UNKNOWN, 3.2: UNKNOWN, 3.3: UNKNOWN to 3.0: DONTNEED, 3.1: DONTNEED, 3.2: DONTNEED, 3.3: REQUIRED

[nobu (Nobuyoshi Nakada)]

• Status changed from Open to Closed

Applied in changeset git|b176315827d1082f43628013a7d89fda02724d33.

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[Bug #20324] Uncomparable ranges are not overlapping