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Bug #17218
closedRange#step sometimes behaves unexpectedly with Rational endpoints and increment
Description
I am using the latest stable version. The same behavior exists in 2.6.6.
11:28:25 $ ruby -v
ruby 2.7.2p137 (2020-10-01 revision 5445e04352) [x86_64-darwin19]
When creating an Enumerator::ArithmeticSequence
with Rational endpoints and increment, sometimes inconsistent behavior results due to floating-point approximation in #last
.
x = Rational(10997, 10000)
y = Rational(11, 10)
s = Rational(1, 10000)
puts "#{[x, y, s].map(&:to_f)}" # -> [1.0997, 1.1, 0.0001]
# intention: this contains exactly the precise Rational representations of 1.0997, 1.0998, 1.0999, 1.1
arith_seq = (x..y).step(s)
puts arith_seq.class # -> Enumerator::ArithmeticSequence
# Things look OK
puts arith_seq.first # -> 10997/10000
puts arith_seq.end # -> 11/10
puts arith_seq.step # -> 1/10000
# But the array that we get from #to_a is missing the last element, (11/10)
puts arith_seq.to_a.to_s # -> [(10997/10000), (5499/5000), (10999/10000)]
# This is apparently due to the value of #last
puts arith_seq.last # -> 1.0999999999999999
# The object itself is confused
puts arith_seq.size # -> 4
puts arith_seq.to_a.size # -> 3
The issue is in the Enumerator::ArithmeticSequence
instance we get when we call Range#step
without a block. The Range#step
method passes the right things when it gets a block.
block_vals = []
(x..y).step(s) { |v| block_vals << v }
puts block_vals.to_s # -> [(10997/10000), (5499/5000), (10999/10000), (11/10)]
I would expect arith_seq.last
to be the exact value Rational(11, 10)
. After all, arith_seq
was created from a Range
with Rational
endpoints and given a rational step size.
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