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Bug #10713

closed

Assigning default value for a Hash as an empty Array creating unpredictable results

Added by punjab (Arvinder Singh) almost 10 years ago. Updated almost 10 years ago.

Status:
Rejected
Assignee:
-
Target version:
ruby -v:
ruby 2.2.0p0 (2014-12-25 revision 49005) [x86_64-darwin14]
[ruby-core:67412]

Description

Creating a Hash with a default value works fine, unless the default value is an empty Array.

E.g. the following returns an empty Hash...

irb(main):001:0> letters = Hash.new([])
=> {}
irb(main):002:0> letters[:a] << 1
=> [1]
irb(main):003:0> letters[:a] << 2
=> [1, 2]
irb(main):004:0> letters[:a]
=> [1, 2]
irb(main):005:0> letters
=> {}

whereas the following code explicitly defining hash keys works.

irb(main):001:0> letters = {a: [], b: []}
=> {:a=>[], :b=>[]}
irb(main):002:0> letters[:a] << 1
=> [1]
irb(main):003:0> letters[:a] << 2
=> [1, 2]
irb(main):004:0> letters[:a]
=> [1, 2]
irb(main):005:0> letters
=> {:a=>[1, 2], :b=>[]}

Is this an unpredictable(bug) or an expected behavior(feature). I tend to lean towards the former, but I might be wrong.

Updated by hsbt (Hiroshi SHIBATA) almost 10 years ago

  • Status changed from Open to Rejected

It's expected behavior

Updated by duerst (Martin Dürst) almost 10 years ago

Hiroshi SHIBATA wrote:

It's expected behavior

Hiroshi, can you tell us why it's expected behavior? It looks quite surprising.

Updated by donburks (Don Burks) almost 10 years ago

Martin Dürst wrote:

Hiroshi SHIBATA wrote:

It's expected behavior

Hiroshi, can you tell us why it's expected behavior? It looks quite surprising.

I would agree that this is surprising behaviour. It would appear that in this case, the append operator is not re-assigning the value, the way it does any other time it is used. And it would appear to be not doing this specifically in the case where the default value for the Hash is specified as an empty array. I would like to understand why this behaviour is the way it is.

Updated by austin (Austin Ziegler) almost 10 years ago

It's quite expected because the default array is created exactly once:

letters = Hash.new([])
letters.default.object_id # => 70310393550400
letters[:a].object_id # => 70310393550400
letters[:b].object_id # => 70310393550400

The pattern that Arvinder wants is:

letters = Hash.new { |h, k| h[k] = [] }
letters.default # => nil
letters.default_proc # => #Proc:0x007fe4d4099988@(irb):7
letters[:a].object_id # => 70310393174180
letters[:b].object_id # => 70310393171680

It's possible to make the correct pattern do the "wrong thing":

array = []
array.object_id # => 70310393550400
letters = Hash.new { |h, k| h[k] = array }
letters.default # => nil
letters.default_proc # => #Proc:0x007fe4d4099988@(irb):7
letters[:a].object_id # => 70310393550400
letters[:b].object_id # => 70310393550400

-a

On Wed, Jan 7, 2015 at 8:16 PM, wrote:

Issue #10713 has been updated by Martin Dürst.

Hiroshi SHIBATA wrote:

It's expected behavior

Hiroshi, can you tell us why it's expected behavior? It looks quite
surprising.


Bug #10713: Assigning default value for a Hash as an empty Array creating
unpredictable results
https://bugs.ruby-lang.org/issues/10713#change-50846

  • Author: Arvinder Singh
  • Status: Rejected
  • Priority: Normal
  • Assignee:
  • Category: core
  • Target version: current: 2.2.0
  • ruby -v: ruby 2.2.0p0 (2014-12-25 revision 49005) [x86_64-darwin14]
  • Backport: 2.0.0: UNKNOWN, 2.1: UNKNOWN, 2.2: UNKNOWN

Creating a Hash with a default value works fine, unless the default value
is an empty Array.

E.g. the following returns an empty Hash...

irb(main):001:0> letters = Hash.new([])
=> {}
irb(main):002:0> letters[:a] << 1
=> [1]
irb(main):003:0> letters[:a] << 2
=> [1, 2]
irb(main):004:0> letters[:a]
=> [1, 2]
irb(main):005:0> letters
=> {}

whereas the following code explicitly defining hash keys works.

irb(main):001:0> letters = {a: [], b: []}
=> {:a=>[], :b=>[]}
irb(main):002:0> letters[:a] << 1
=> [1]
irb(main):003:0> letters[:a] << 2
=> [1, 2]
irb(main):004:0> letters[:a]
=> [1, 2]
irb(main):005:0> letters
=> {:a=>[1, 2], :b=>[]}

Is this an unpredictable(bug) or an expected behavior(feature). I tend to
lean towards the former, but I might be wrong.

--
https://bugs.ruby-lang.org/

--
Austin Ziegler * *
http://www.halostatue.ca/ * http://twitter.com/halostatue

Updated by david_macmahon (David MacMahon) almost 10 years ago

Arvinder Singh wrote:

irb(main):001:0> letters = Hash.new([])
=> {}
irb(main):002:0> letters[:a] << 1
=> [1]

The letters[:a] part of the second line returns the "default value" of the Hash because the :a key does not exist in the Hash. The << 1 part pushes a 1 onto the end of the default value, but it does not assign the default value (and certainly not a modified copy of the default value) to the :a key of the Hash.

To get the behavior you expect/desire you can use letters[:a] <<= 1, which is equivalent to letters[:a] = letters[:a] << 1, but be careful when using Hashes with default objects:

irb(main):001:0> letters = Hash.new([]) # Default object == single instance
=> {}
irb(main):002:0> letters[:a] <<= 1
=> [1]
irb(main):003:0> letters[:a]
=> [1]
irb(main):004:0> letters
=> {:a=>[1]}
irb(main):005:0> letters[:b] # Returns default object (same object as letters[:a])!
=> [1]

To get a different object for each fetch of a non-existent key, use a Hash with a default Proc that returns new object every time:

irb(main):001:0> letters = Hash.new {[]} # Default Proc returns new instance each call
=> {}
irb(main):002:0> letters[:a] <<= 1
=> [1]
irb(main):003:0> letters[:a]
=> [1]
irb(main):004:0> letters
=> {:a=>[1]}
irb(main):005:0> letters[:b] # Returns different empty Array until letters[:b] is assigned
=> []
irb(main):006:0> letters[:b].object_id
=> 2152992900
irb(main):007:0> letters[:b].object_id
=> 2153118760
irb(main):008:0> letters[:b].object_id
=> 2153112180
irb(main):009:0> letters[:b] = letters[:b]
=> []
irb(main):010:0> letters[:b].object_id
=> 2156907140
irb(main):011:0> letters[:b].object_id
=> 2156907140

Given all the trickiness and because sometimes you don't have control over the creation of the Hash, I generally end up doing this instead:

>> # h is any Hash, e.g. from method call
>> h[:a] ||= []
=> []
>> h[:a] << 1
=> [1]
# etc...

This uses the "||=" idiom, which can obliterate an existing nil or false value, so you still have to be a little careful (though it's very rarely an issue).

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